10018-Reverse and Add

<br /> /* <br /> "Reverse and Add"<br /> Level:2.5<br /> Date:2006/10/2<br /> 技巧:一個數字如:591 可以看成 ((5*10)+9)*10+1<br /> 要轉成195 即 ((1*10)+9)*10+5<br /> */<br /> #include <stdio.h><br /> unsigned long reverse(unsigned long);<br /> <br /> main(){<br /> long int input=0;<br /> long int rev=0;<br /> int n=0,iter=0;<br /> scanf("%d",&n);<br /> while(n-- > 0){ <br /> scanf("%lu",&input);<br /> while(rev !=input){<br /> input+=rev;<br /> rev = reverse(input);<br /> iter++;<br /> } <br /> printf("%d %lu\n",--iter,rev);<br /> rev=iter=0; <br /> } <br /> } <br /> <br /> unsigned long int reverse(unsigned long a){<br /> unsigned long r=0;<br /> while(a!=0){<br /> r=r*10;<br /> r += a%10;<br /> a /= 10; <br /> }<br /> return r; <br /> }<br />